The total number of electrons removed from the neutral silver dollar is [tex]1.5 \times 10^{13}[/tex] electrons.
A charge can be defined as a property of any matter that causes it to experience a force when it's placed in an electric or magnetic field. The electron is negatively charged. The value of an electron charge is [tex]1.6\times 10^{-19}\;\rm C[/tex]
Given that the neutral silver dollar has a charge [tex]q = +2.4 \mu \rm C[/tex] .
The charge can be given as,
[tex]q=ne[/tex]
Where n is the number of electrons. Thus,
[tex]n =\dfrac { q}{e}[/tex]
[tex]n = \dfrac {+2.4 \times 10 ^{-6}}{1.6\times 10^{-19}}[/tex]
[tex]n = 1.5 \times 10^{13}[/tex]
Hence we can conclude that the total number of electrons removed from the neutral silver dollar is [tex]1.5 \times 10^{13}[/tex] electrons.
To know more about the charge and electron, follow the link given below.
https://brainly.com/question/2553023.
