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What is the equation of this circle in general form? x² + y² + 2x + 6y + 4 = 0 x2+y2−2x−6y−26=0 x2+y2−2x−6y+4=0 x2+y2+2x+6y−26=0 a circle on a coordinate plane centered at begin ordered pair 1 comma 3 end ordered pair. the horizontal x-axis ranges from negative 10 to 10 increments of 1. the vertical y-axis ranges from negative 10 to 10 in increments of 1. the circle passes through begin ordered pair negative 5 comma 3 end ordered pair, begin ordered pair 1 comma 9 end ordered pair, begin ordered pair 7 comma 3 end ordered pair, and begin ordered pair 1 comma negative 3 end ordered pair?

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x²+y²-2x-6y-26=0 
Just took the quiz, this is it

A circle on a coordinate plane is centered at the beginning ordered (1, 3). The equation of the circle is x²+y²-2x-6y-26=0

What is the equation of the circle with radius r units, centered at (x,y)?

If a circle O has radius of r units length and that it has got its center positioned at (h, k) point of the coordinate plane, then, its equation is given as:

[tex](x-h)^2 + (y-k)^2 = r^2[/tex]

A circle on a coordinate plane is centered at the beginning ordered (1, 3).

The horizontal x-axis ranges from negative 10 to 10 increments of 1. and the vertical y-axis ranges from negative 10 to 10 in increments of 1.

The equation of the circle is

[tex]x^2+y^2-2x-6y-26=0[/tex]  

Learn more about the equation of a circle here:

https://brainly.com/question/10165274

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