we can first find the number of moles of nitrogen gas in the container using th ideal gas law equation
PV = nRT
where P - pressure - 112 100 Pa
V - volume - 8.86 x 10⁻³ m³
n - number of moles
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature in kelvin - 30.8 °C + 273.15 = 303.95 K
substituting these values in the equation
112 100 Pa x 8.86 x 10⁻³ m³ = n x 8.314 Jmol⁻¹K⁻¹ x 303.95 K
n = 0.393 mol
number of N₂ moles are 0.393 mol
In 1 mol of N₂ there are 6.022 x 10²³ molecules of N₂
therefore in 0.393 mol - 6.022 x 10²³ mol⁻¹ x 0.393 mol = 2.37 x 10²³
there are 2.37 x 10²³ molecules of N₂
