Respuesta :

Answer:
             [H⁺]  =  5.011 × 10⁻³ mol.L⁻¹

Explanation:

The pH is converted into concentration of H⁺ as,

[H⁺]  = 10^-pH

Where 10 is antilog,

So, putting values,

[H⁺]  =  10⁻²·³

[H⁺]  =  0.00501

Or,

[H⁺]  =  5.011 × 10⁻³ mol.L⁻¹