Respuesta :
PbCrO₄ is made of a cation and anion
anion is CrO₄²⁻
we need to then find the oxidation number of Pb which is the same as its charge
when we make compounds, the charges of the cations and anions are exchanged.
Charge of Pb is then Pb²⁺
since charge of monoatomic ion is equal to oxidation number of the ion
oxidation number of Pb = +2
net charge of CrO₄²⁻ is -2
oxidation number of Cr + (4 x oxidation number of O) = -2
oxidation number of O is usually -2
oxidation number of Cr = y
y + (4 x -2 ) = -2
y - 8 = -2
y = +6
oxidation number of Cr is +6
answer is
3. pb = +2, cr = +6
anion is CrO₄²⁻
we need to then find the oxidation number of Pb which is the same as its charge
when we make compounds, the charges of the cations and anions are exchanged.
Charge of Pb is then Pb²⁺
since charge of monoatomic ion is equal to oxidation number of the ion
oxidation number of Pb = +2
net charge of CrO₄²⁻ is -2
oxidation number of Cr + (4 x oxidation number of O) = -2
oxidation number of O is usually -2
oxidation number of Cr = y
y + (4 x -2 ) = -2
y - 8 = -2
y = +6
oxidation number of Cr is +6
answer is
3. pb = +2, cr = +6
The oxidation state of the lead and chromium metal in the PbCrO₄ compound is +2 and +6 respectively.
What is oxidation state?
Oxidation state of any atom tells about the number of exchangeable electrons from the outermost shell of that atom.
As we know that in the compound PbCrO₄, CrO₄ is an anion and charge on this is -2 i.e. it is represented as CrO₄²⁻. We know that oxidation state of each oxygen atom is -2 and let us assume the oxidation state of chromium is y, so we calculate the value of y for CrO₄²⁻ as:
y + 4(-2) = -2
y = -2 + 8 = 6
Let the oxidation state of lead is x and calculation for that from PbCrO₄ will be done as:
x + 6 + 4(-2) = 0
x = 8 - 6 = 2
Oxidation state of Pb is +2 and of Cr is +6.
To know more about oxidation state, visit the below link:
https://brainly.com/question/8990767
