Respuesta :

skyluke89
The frequency of a wave is the reciprocal of its period, so for the wave in this problem, its frequency is
[tex]f= \frac{1}{T}= \frac{1}{0.0125 s} =80 Hz [/tex]

The basic relationship between wavelength, frequency and speed of a wave is given by:
[tex]\lambda= \frac{v}{f}[/tex]
where
[tex]\lambda[/tex] is the wavelength of the wave
v is its speed
f is its frequency

If we plug the numbers given by the problem into this equation, we can find the wavelength of this wave:
[tex]\lambda= \frac{v}{f}= \frac{3.26 \cdot 10^6 m/s}{80 Hz}=4.08 \cdot 10^4 m=40.8 km[/tex]
udeakuudenze

Answer:

m=40.8km.

Explanation:

  • The frequency of a wave is the reciprocal of its period, so for the wave in this problem, its frequency is
  • f= \frac{1}{T}= \frac{1}{0.0125 s} =80 Hzf=

T

1

=

  • 0.0125s

1

=80Hz

The basic relationship bet

where

\lambdaλ is the wavelength of the wave

v is its speed

f is its frequency

If we plug the numbers given by the problem into this equation, we can find the wavelength of this wave:

\lambda= \frac{v}{f}= \frac{3.26 \cdot 10^6 m/s}{80 Hz}=4.08 \cdot 10^4 m=40.8 kmλ=

f v

=

80Hz

3.26⋅10

6

m/s

=4.08⋅10

4

m=40.8km

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