contestada

Find the amount of work done in vertically lifting a steel beam of mass 600. kg at uniform speed through a distance of 38.0 m.

Respuesta :

skyluke89
The work done in lifting the steel beam is equal to its increase in gravitational potential energy:
[tex]W=mg \Delta h[/tex]
where
m is the mass of the steel beam
g is the gravitational acceleration
[tex]\Delta h[/tex] is the variation of height of the object

In this problem, m=600 kg and [tex]\Delta h=38.0 m[/tex], therefore the work done to lift the object is
[tex]W=(600 kg)(9.81 m/s^2)(38.0 m)=2.24 \cdot 10^5 J[/tex]
pstnonsonjoku

From the calculations, we can see that the work done in the gravitational field is 228000J

What is work done?

The work done in a gravitational field depends on the height of the body hence we have;

Work done = mgh

m = 600 kg

g = 10 m/s^2

h = 38 m

Hence

W = 600 kg *  10 m/s^2 * 38 m = 228000J

Learn more about work done:https://brainly.com/question/13662169?

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