rc132923
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Which formula can be used to calculate the horizontal displacement of a horizontally launched projectile?

x = vi(cos )
x = vi(cos )t
x = ayt
x = vxt (RIGHT ANSWER)

Respuesta :

egenriether
Well, the displacement is velocity times time.  The horizontal displacement is then the horizontal component of velocity times time.  The horizontal component is given by the initial total velocity times the cosine of the angle.  If Vi is the initial velocity then choice 2 is right.  It is also possible Vx is meant as the x-component of the total velocity in which the last answer is also correct.  It would help to recreate the problem variables in the math equation editor, or define what you mean by "vi(cos )t"  and "vxt".  These are somewhat vague descriptions.  Hope this helped
Cricetus

The formula for calculating the horizontal displacement of a horizontally launched projectile is [tex]x=v*t[/tex]

A projectile launched horizontally with a velocity v, at a height y ,travels a horizontal distance x, while falling through a distance y. The horizontal velocity of a projectile remains constant throughout its motion, in the absence of air resistance. The vertical component of the velocity is under the action of the gravitational force and hence it increases in magnitude as it falls through the height.

The horizontal displacement of the projectile is a uniform motion and it occurs at a constant speed v.

Thus, the horizontal displacement of the projectile is given by the expression.

[tex]x=v*t[/tex]