A tank contains 651 L of oxygen gas at 122 atm and 25 °C. A the same temperature and 745 Torr, it occupies 8.10 × 10⁴ L.
Oxygen gas occupies 651 L (V₁) at 122 atm (P₁) and 25.0 °C.
We will convert 122 atm to Torr using the conversion factor 1 atm = 760 Torr.
[tex]122 atm \times \frac{760Torr}{1atm} = 9.27 \times 10^{4} Torr[/tex]
Then, the pressure is decreased to 745 Torr (P₂) and the temperature remains constant. We can calculate the new volume (V₂) occupied by the oxygen gas using Boyle's law.
[tex]P_1 \times V_1 = P_2 \times V_2\\\\V_2 = \frac{P_1 \times V_1}{P_2} = \frac{9.27 \times 10^{4} Torr \times 651L}{745Torr} = 8.10 \times 10^{4} L[/tex]
A tank contains 651 L of oxygen gas at 122 atm and 25 °C. A the same temperature and 745 Torr, it occupies 8.10 × 10⁴ L.
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