An equation is formed of two equal expressions. The two solutions of equation 2√2cosx-4(sinx)cosx =0 are at π/2 and π/4.
An equation is formed when two equal expressions are equated together with the help of an equal sign '='.
The solution of the equation 2√2cosx-4 sinx cosx =0 can be found by factorizing the given equation, therefore, the solution is,
2√2cosx-4 sinx cosx =0
2cosx(√2-2sinx)=0
(2cosx-0)(√2-2sinx)=0
(2cosx-0)=0
2cosx-0 = 0
2cosx=0
cosx = 0/2
cosx=0
x = cos⁻¹(0)
x = π/2
(√2-2sinx)=0
2sinx = √2
sinx = (√2)/2
x = sin⁻¹[1/(√2)]
x = π/4
Hence, the two solutions of equation 2√2cosx-4(sinx)cosx =0 are at π/2 and π/4.
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