Respuesta :
well, first off, let's check how far is it on the map, from the library to his dorm,
[tex]\bf \textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({{ 4}}\quad ,&{{ 0}})\quad % (c,d) &({{ 12}}\quad ,&{{ 6}}) \end{array}\qquad % distance value d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2} \\\\\\ d=\sqrt{(12-4)^2+(6-0)^2}\implies d=\sqrt{8^2+6^2}\implies d=\sqrt{64+36} \\\\\\ d=\sqrt{100}\implies d=10[/tex]
so there are that many units, now, how many miles is that?
well, we know each map unit is 0.75 miles, so there are d * 0.75 miles then
[tex]\bf \textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({{ 4}}\quad ,&{{ 0}})\quad % (c,d) &({{ 12}}\quad ,&{{ 6}}) \end{array}\qquad % distance value d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2} \\\\\\ d=\sqrt{(12-4)^2+(6-0)^2}\implies d=\sqrt{8^2+6^2}\implies d=\sqrt{64+36} \\\\\\ d=\sqrt{100}\implies d=10[/tex]
so there are that many units, now, how many miles is that?
well, we know each map unit is 0.75 miles, so there are d * 0.75 miles then
Answer:
7.5 miles.
Step-by-step explanation:
It is given that on a coordinate map the local library located at (4, 0) dorm located at (12, 6).
Distance formula:
[tex]Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Using distance formula, the distance between library and dorm is
[tex]Distance=\sqrt{(12-4)^2+(6-0)^2}[/tex]
[tex]Distance=\sqrt{(8)^2+(6)^2}[/tex]
[tex]Distance=\sqrt{64+36}[/tex]
[tex]Distance=\sqrt{100}[/tex]
[tex]Distance=10[/tex]
The distance between library and dorm is 10 units.
It is given that each unit represents 0.75 miles.
1 unit = 0.75 miles
10 units = 7.5 miles
Therefore, the actual distance between library and dorm is 7.5 miles.