Calculation type
(1) Calculate the mass of
magnesium metal used in
trial #1.
Use your data table for "B"
and "A"
(2) Subtract the mass of the
crucible and lid from the total
mass of MgO, crucible, and
lid to find the mass of
magnesium oxide for trial 2.
Use your data table for "C"
and "A"
Trial #1 (Show your work below)
Mass of Mg="B" - "A"
Mass of Mg=?
Mass of Mg= ? |
-
?
Mass of MgO=(Mass of crucible, lid, and MgO) - (Mass of empty
crucible)
Mass of MgO="C" - "A"
Mass of MgO= ? - ?
Mass of MgO= ? (this is the actual yield of MgO)
(3) Magnesium is the limiting Step 1: ?g Mg X
reactant in this experiment.
Calculate the theoretical
yield of MgO for trial #1.
3 steps:
Mass of Mg to mol Mg
Mol Mg to mol MgO
Mol MgO to mass MgO
(4) Determine the percent
yield of MgO for your
experiment for trial #1.
1 mol Mg
? molar mass of Mg
= ? mol Mg
Step 2: ? mol Mg X ? mol MgO = ? mol MgO
? mol Mg
Step 3: ? mol MgO X ? molar mass of MgO = ? g MgO
1 mol MgO
(the final answer here is the theoretical yield of MgO)
% Yield trial 1 =
% Yield trial 1 =
? actual yield from (2) above
? theoretical yield from(3) above
X 100
it’s from the calculations for trial one for flvs 5.07 percent yield lab report please help