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10-04-2017
Chemistry

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anonymous79 anonymous79

04-06-2017

4Al + 3O2 --> 2Al2O3
2Al2O3 + 6HCL --> 2AlCl3 + 3H2O
Number of moles of Al= 0.02mol
Number of mples of Al2O3 = 0.01mol
Number of HCl needed= 0.01mol * 3 =0.03mol
Minimum volume = 0.03mol / 2molperdm^3= 0.015dm^3 =15cm^3
Answer is A

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