Find two z values, one positive and one negative, that are equidistant from the mean SO that the areas in the two tails add to 5% A) z =+1,96 and z = -1,96 B) 2 =+0.13andz =-0.13 2= +1.65 and 2 =-1.65 D) z = +2.58 and z =-2.58

Respuesta :

The two z values are -1.96 and +1.96 this means that option A is the correct choice.

From the given information we know that P(-z<Z or Z>z) = 5% = 0.05.

Then the table (area under the normal curve) the probability of values smaller than a certain z-score of the standard normal distribution.

Now the standard normal distribution is symmetric about 0.

P(-z<Z)=P(-z<Z or Z>z)/2

P(-z<Z)=0.05/2

P(-z<Z)=0.025

Here we have to determine the corresponding z-score in area under the normal curve table.

The corresponding z-score z is then given in row/column title of area under the normal curve table which corresponding to a probability of 0.025 or the probability closest.

-z = -1.96

Two z -values , positive and negative that are equidistance from the mean so that the area in two tailed total 5% are,

= ±1.967 = ±1.96

z=-1.96,+1.96

Therefore, the correct option is A.

To learn more about standard normal distribution check the link below:

https://brainly.com/question/26822684

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