help!! please its easy
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The area of the quadrilateral ABCD is 26 square units
The quadrilateral ABCD is a trapezoid, and it has the following parameters:
The lengths of these sides can be calculated using
d = √[(x2 - x1)^2 +(y2 - y1)^2]
So, we have
BC = √[(0 - 4)^2 +(3 + 1)^2] = 4√2
AD = √[(-5 - 4)^2 +(4 + 5)^2] = 9√2
CE = √[(2 - 4)^2 +(-3 + 1)^2] = 2√2
The area of the quadrilateral ABCD is then calculated as
Area = 0.5 * (BC + AD) * CE
This gives
Area = 0.5 * (4√2 + 9√2) * 2√2
Evaluate
Area = 26
Hence, the area of the quadrilateral ABCD is 26 square units
Read more about areas at:
brainly.com/question/22972014
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