Answer:
Atomic mass of the element = 80.80 amu
Explanation:
Given:
Mass of element = 4.00 g
No. of atoms = [tex]2.98\times 10^{22}[/tex]
[tex]mol = \frac{No.\ of\ atoms}{Avogadro's\ no.}[/tex]
Avogadro's no. = tex]6.02\times 10^{23}[/tex]
[tex]mol = \frac{No.\ of\ atoms}{Avogadro's\ no.}[/tex]
=[tex]\frac{2.98\times 10^{22}}{6.02\times 10^{23}} = 0.0495\ mol[/tex]
Formula for moles in the terms of mass and atomic mass
[tex]mol = \frac{Mass\ in\ g}{Atomic\ mass} \\Atomic\ mass = \frac{Mass\ in\ g}{mol}[/tex]
Atomic mass of the element = [tex]\frac{4.00}{0.0495} = 80.80\ amu[/tex]
Atomic mass of the element = 80.80 amu
