Answer:
If fluorine were to react with an element such as sodium, fluorine will recieve the all of sodium's valence electrons (1). This means both elements will fulfil the octet rule; valence electrons shells are full.
Explanation:
Electrons are transferred because of the difference in electronegativity
Fluorine = 3.98
Sodium = 0.93
3.98 - 0.93 = 3.05
Δ Electronegativity = 3.05
This falls in the range of 2.0 - 4.0 which means the bond is an ionic bond. In an ionic bond, all valence electrons of the metal (sodium, in this case) are transferred to the non-metal (fluorine, in this case).
Fluorine has 7 valence electrons. when it reacts with an element such as sodium the fluorine will accept one electron from sodium and complete its octave after attending 8 electrons in the outermost shell and attend negative charge.
The octave rule is that every element which is electron deficient will have to obtain 8 electron into it valance shell to become stable according to the rule.
flourine is the electron deficient compound and sodium has an extra electron in its outermost shell and most electronegative element of the periodic table and accepts the electron from the sodium to become stable to follow the octave rule.
Therefore, fluorine has 7 valence electrons. when it reacts with an element such as sodium the fluorine will accept one electron from sodium and complete its octave after attending 8 electrons in the outermost shell and attend negative charge.
Learn more about octave rule, here:
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