Respuesta :
The distance the spring will be stretched with an object weighing 29 kilograms is 47 centimeters
Variation
From the question, we are to determine the distance the spring will be stretched with an object weighing 29 kg
From the given information,
The distance, D, that a spring is stretched by a hanging object varies directly as the weight, W, if the object
That is,
D ∝ W
Then, we can write that
D = kW
NOTE: k is the constant of proportionality
Also, from the given information,
An object weighing 30 kilograms stretched the spring 49 centimeters
That is,
D = 49 cm
W = 30 kg
Putting the parameters into the equation to solve for k, we get
49 = k × 30
∴ k = 49/30
Now, for the distance stretched when weight is 29 kg
Using D = kW, we get
D = (49/30) × 29
D = 1421/30
D = 47.367
D ≅ 47 cm
Hence, the distance the spring will be stretched with an object weighing 29 kilograms is 47 centimeters
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