The value of x, y and z from the system of equation are -1, -8 and 5 respectively.
Data;
- -2x + 6y + 3z = -31
- -3y + 7z = 59
- 2z = 10
System of Equation
To solve this problem, we have to solve the system of equation using substitution method.
From equation (iii)
[tex]2z = 10\\z = 5[/tex]
let us substitute the value of z into equation (ii)
[tex]-3y + 7z = 59\\z = 5\\-3y + 7(5) = 59\\-3y + 35 = 59\\-3y = 59 - 35\\-3y = 24\\y = -8[/tex]
Let's substitute the value of x and y into equation (i)
[tex]-2x + 6y + 3z = -31\\y = -8, z = 5\\-2x + 6(-8) + 3(5) = -31\\-2x - 48 + 15 = -31\\-2x - 33 = -31\\-2x = -31 + 33\\-2x = 2\\x = -1[/tex]
From the calculation above, the value of x, y and z are -1, -8 and 5 respectively.
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