In a bolt of lightning, 45, n, C,45nC flows to ground in 25, m, s,25ms. Work out the average number of charge carriers flowing past per second.

If 56, times, 10, to the power 16 ,56×10 16 electrons flow to the ground in 0, point, 035, mu, s,0.035μs, work out the average current.

How long does it take for a current of 6, point, 0, A,6.0A to deliver 1, point, 5, times, 10, to the power 17 ,1.5×10 17 [[Unsupported equation]]CuX
2+ ions in a solution? Assume these ions are the only charged particles moving.

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onyebuchinnaji onyebuchinnaji · Answer 1 · 2022-03-21T12:38:49+01:00

(a) The average number of charge carriers flowing past per second is 1.8 x 10⁻⁶ A

(b) The average current delivered in the given time is 2.56 x 10⁶ A.

(c) The time taken to deliver the charge is 32,166.7 s.

The average number of charge flowing per second is calculated as follows;

I = Q/t

I = (45 x 10⁻⁹) / (25 x 10⁻³)

I = 1.8 x 10⁻⁶ A = 1.8μ A

The average current is number of charge flowing in a second.

I = Q/t

Charge of one electron = 1.6 x 10⁻¹⁹ C

Charge of 56 x 10¹⁶ electrons = 56 x 10¹⁶ x 1.6 x 10⁻¹⁹ C = 0.0896 C

I = (0.0896) / (0.035 x 10⁻⁶)

I = 2.56 x 10⁶ A

Total charge in 2+ ions = 2F

1 Faraday = 96,500 C

2F = 2 x 96,500 C = 193,000 C

At the given amount of current, the time taken to deliver the charge is calculated as follows;

Q = It

t = Q/I

t = (193,000 )/6

t = 32,166.7 s = 8.9 hours

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