This problem is providing describing a room in which air has a total pressure of 0.987 atm and the partial pressure of nitrogen is asked, turning out to be 0.746 atm.
In such a case, we can start by looking at the provided table, which shows the composition of dry air in mass basis, which means we must convert the composition of nitrogen to mole fraction by knowing that the average molar mass of air is 28.9647 g/mol, and thus, we infer that the mole fraction of nitrogen in air is about 0.755 according to:
[tex]x_{N_2}=\frac{0.781*14.0067g/mol*2}{28.9647g/mol} =0.755[/tex]
Then, we recall the Dalton's law version that relates total pressure, partial pressure and mole fraction written for nitrogen:
[tex]P_{N_2}=x_{N_2}P[/tex]
Finally, we plug in the previously calculated mole fraction and the total pressure of air to obtain:
[tex]P_{N_2}=0.755*0.987 atm\\\\P_{N_2}=0.746atm[/tex]
Learn more:
- (Gas laws) https://brainly.com/question/8511562
- (Dalton's law) https://brainly.com/question/14119417
