contestada

A block of mass 1.0 kg rests on a trolley of mass 4.0 kg. The coefficient of dynamic friction between the block and the trolley is 0.30. A horizontal force f = 5.0 n acts on the block. The block slides over the trolley. What is the acceleration of the trolley?

Respuesta :

Answer:

the acceleration of the trolley is the acceleration of the trolley is 0.75 m/s^-2

Explanation:

friction force between the block and the trolley

= 1×0.3×9.8

= 2.94 N

(F = ma)

the acceleration of the trolley

= friction force/mass

= 2.94/4

= 0.735 m/s^-2

= 0.75 m/s^-2

The acceleration of the trolley will be 0.75 m/s².Acceleration is the ratio of the force to the mass.

What is the friction force?

It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. its unit is Newton (N).

Mathematically it is defined as the product of the coefficient of friction and normal reaction.

The friction force between the block and the trolley is found as;

[tex]\rm F_f = \mu N \\\\ \rm F_f = \mu \times mg \\\\ \rm F_f = 0.30 \times 1 \timess 9.81 \\\\ \rm F_f= 2.94 \ N[/tex]

Mechanical force is equal to the product of the mass and the acceleration which is equal to the frictional force;

[tex]\rm F_f =F=ma \\\\ \rm a = \frac{F}{m} \\\\ \rm a = \frac{2.94}{4} \\\\ a=0.735 \ ms^{-2}[/tex]

Hence the acceleration of the trolley will be 0.75 m/s².Acceleration is the ratio of the force to the mass.

To learn more about the friction force refer to the link;

https://brainly.com/question/1714663