The center of mass of the two objects is the average position of the parts of the two object system
The center of mass of block A, and block B after displacement of block B is at 20 m from block A
Reason:
The given parameters are;
The position of block A and block B at t = 0 is x = 0
The mass of block A, m₁ = 8 kg
Mass of block B, m₂ = 16 kg
Speed of block A = 0 m/s
Speed of block B, v₂ = 10 m/s
Location of the center of mass of the two object at t = 3 s; Required
Solution;
The location of block A, after 3 s is x₁ = 0 (block A is at rest)
The location of block B, = v₂ × t
The location of block B, after 3 s is x₂ = 10 m/s × 3 s = 30 m
The center of mass of two masses are given as follows;
[tex]x_{cm} = \dfrac{m_1 \cdot x_1 +m_2\cdot x_2}{m_1 + m_2}[/tex]
[tex]x_{cm} = \dfrac{8 \times0 + 16 \times 30}{8 + 16} = 20[/tex]
The center of mass of the two objects is at at the position x = 20 m (from block A)
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