Answer:
(x²+1)(x²-1)⁶ = x¹⁴-5x¹²+9x¹⁰-5x⁸-5x⁶+9x⁴-5x²+1
Step-by-step explanation:
Pascal triangle 6th row for (a + (-b))⁶; ... for (x²-1)⁶
a⁶+6a⁵(b)¹+15a⁴(b)²+20a³(b)³+15a²(b)⁴+6a(b)⁵+1*(b)⁶ .. a=x² b = -1
= x¹²+6x¹⁰(-1)¹+15x⁸(-1)²+20x⁶(-1)³+15x⁴(-1)⁴+6x²(-1)⁵+1*(-1)⁶
= x¹²-6x¹⁰+15x⁸-20x⁶+15x⁴-6x²+1
(x²+1)(x²-1)⁶ = (x²+1)(x¹²-6x¹⁰+15x⁸-20x⁶+15x⁴-6x²+1)
= x¹⁴-5x¹²+9x¹⁰-5x⁸-5x⁶+9x⁴-5x²+1
