Answer:
Option B
Step-by-step explanation:
Slope of a line passing through two points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is given by,
Slope (m) = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
Therefore, slope of the line passing through (-5, -2) and (3, -1) will be,
m = [tex]\frac{-1+2}{3+5}[/tex]
m = [tex]\frac{1}{8}[/tex]
Equation of the line passing through (h, k) and slope 'm' is given by,
y - k = m(x - h)
Therefore, equation of the line passing through (3, -1) and slope = [tex]\frac{1}{8}[/tex] will be,
[tex]y+1=\frac{1}{8}(x-3)[/tex]
[tex]y=\frac{1}{8}x-\frac{3}{8}-1[/tex]
[tex]y=\frac{1}{8}x-\frac{11}{8}[/tex]
Option B will be the answer.
