Answer:
[tex]x^{\frac{1}{8} } y^{8}[/tex]
Step-by-step explanation:
Given :
[tex](x^\frac{1}{4} y^{16} )^{1/2}[/tex]
Now,
[tex](x^\frac{1}{4} y^{16} )^{1/2}\\x^{\frac{1}{8} } y^{8}[/tex]
Therefore, expression is equivalent to [tex]x^{\frac{1}{8} } y^{8}[/tex]