The mayor of a town has proposed a plan for the annexation of a new community. A political study took a sample of 900900 voters in the town and found that 42B% of the residents favored annexation. Using the data, a political strategist wants to test the claim that the percentage of residents who favor annexation is above 388%. Find the value of the test statistic. Round your answer to two decimal places.

Respuesta :

Answer:

The value of the test statistic is 2.47.

Step-by-step explanation:

The test statistic is:

[tex]t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the expected mean, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.

For a proportion p, we have that:

[tex]s = \frac{\sigma}{\sqrt{n}} = \sqrt{\frac{p(1-p)}{n}}[/tex]

A political study took a sample of 900 voters in the town and found that 42% of the residents favored annexation.

This means that [tex]X = 0.42, n = 900[/tex]

Using the data, a political strategist wants to test the claim that the percentage of residents who favor annexation is above 38%

This means that the expected is [tex]\mu = p = 0.38[/tex]

So

[tex]s = \frac{\sigma}{\sqrt{n}} = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.38*0.62}{900}} = 0.0162[/tex]

Find the value of the test statistic

[tex]t = \frac{X - \mu}{s}[/tex]

[tex]t = \frac{0.42 - 0.38}{0.0162}[/tex]

[tex]t = 2.47[/tex]

The value of the test statistic is 2.47.