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A metal cube 1.0 cm on each side is sandwiched between two electrodes. The electrodes create a 0.0050N/C electric field in the metal. A current of 9.0 A passes through the cube, from the positive electrode to the negative electrode. Identify the metal.
a-Tungsten
b-gold
c-silver
d-copper

Respuesta :

Answer:

This is Tungsten .

Explanation:

Electrical field E = V / l , V is potential diff and l is length

.005 = V / .01

V = .005 X .01 = 5 X 10⁻³ volts

I current = 9A

Resistance R = V / I

= 5 x 10⁻³ / 9

= 5.55 x 10⁻⁶ ohm .

To calculate resistivity :

R = ρ l / S , l is length , S is cross sectional area

5.55 x 10⁻⁶ = ρ x .01  / .01 x .01

ρ = 5.5 x 10⁻⁸

This is Tungsten .