Given:
The figure of a trapezoid.
Length of mid-segment = 5.5
Height of the trapezoid = [tex]6\sqrt{3}[/tex]
To find:
The area of the trapezoid.
Solution:
The area of a trapezoid is:
[tex]A=M\times h[/tex] ...(i)
[tex]A=\dfrac{a+b}{2}\times h[/tex]
Where, a,b are bases and h is the vertical height.
We know that [tex]M=\dfrac{a+b}{2}[/tex] is the length of the mid-segment.
Putting M=5.5 and [tex]h=6\sqrt{3}[/tex] in (i), we get
[tex]A=5.5\times 6\sqrt{3}[/tex]
[tex]A=33\sqrt{3}[/tex]
Therefore, the area of the trapezoid is [tex]33\sqrt{3}[/tex] units squared.
