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At a high school, 18% of the students play football and 6% of the students play football and baseball. What is the probability that a student plays baseball given that he plays football?

Respuesta :

Answer:

33.3%

Step-by-step explanation:

Defining:

A: a student plays football

B: a student plays baseball

Data:

P(A∩B): a student plays football and baseball = 0.06

P(A) = 0.18

The probability that a student plays baseball given that he plays football is calculated as follows:

P(B/A) = P(A∩B)/P(A) = 0.06/0.18 = 0.33

Needhelpzzz

Answer: answer above is correct. I just did my final and it was correct

Step-by-step explanation:

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