The correct proof of sin(90-theta)=cos theta is given below.
We have given that
Malia tried to prove that cos(theta) = sin (90 - theta)
What is the formula for sin(a-b)?
The formula for sin(a-b) is sin(a)cos(b)-cos(a)sin(b)
[tex]Sin(90-\theta)=cos\theta[/tex]
[tex]sin(90-\theta)=sin(90)cos(\theta)-cos(90)sin(\theta)\\We \ know\\ sin(90)=1 and cos(90)=0\\=(1)cos(\theta)-(0)sin(\theta)\\=cos(\theta)[/tex]
Therefore we get sin(90-theta)=cos theta.
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