Answer:
AB = 5.8 units
Explanation:
The distance of line segment AB shown in the attachment below can be calculated using the distance formula, [tex] d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex], assuming that each box in the graph equals 1 unit.
A(2, 4)
B(-3, 1)
Let,
[tex] A(2, 4) = (x_1, y_1) [/tex]
[tex] B(-3, 1) = (x_2, y_2) [/tex]
Plug in the values into the distance formula
[tex] d = \sqrt{(-3 - 2)^2 + (1 - 4)^2} [/tex]
[tex] d = \sqrt{(-5)^2 + (-3)^2} [/tex]
[tex] d = \sqrt{25 + 9} [/tex]
[tex] d = \sqrt{34} [/tex]
[tex] d = 5.8 [/tex] (nearest tenth)
AB = 5.8 units
