Answer:
2n^2 + n + 4.
Step-by-step explanation:
7, 14, 25, 40, 59
The differences are 7, 11, 15, 19 which is arithmetic sequence so the given sequence is quadratic.
Compile a table:
n 1 2 3 4 5
term 7 14 25 40 59
Diff: 7 11 15 19
Diff: 4 4 4 - this indicates that first part is 2n^2.
2n^2 2 8 18 32 50
term-2n^2 5 6 7 8 9
- the nth term for the last sequence is 5+ (n - 1)d =
= 5 + (n - 1)* 1
= n + 4.
So nth term for the original sequence is 2n^2 + n + 4.
