Answer:
[tex]\rho=1.10\times 10^{-7}\ \Omega[/tex]
Explanation:
Given that,
The length of the resistance wire, l = 10 m\
The resistance of this wire is 5.65 Ω/m
The diameter of the wire, d = 0.5 mm
Radius, r = 0.25 mm = 0.00025 m
We need to find the resistivity of isachrom 60 at 20°C. The formula for the resistance of a wire is given by :
[tex]R=\rho\dfrac{l}{A}\\\\\rho=\dfrac{RA}{l}\\\\\rho=\dfrac{R\pi r^2}{l}\\\\\rho=\dfrac{5.65\times \pi \times (0.00025)^2}{10}\\\\\rho=1.10\times 10^{-7}\ \Omega[/tex]
The resistivity of the wire is [tex]1.10\times 10^{-7}\ \Omega[/tex].
