Answer:
8.68 g CH₃(CH₂)₈(OH)₂
General Formulas and Concepts:
Math
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Chemistry
Atomic Structure
- Reading a Periodic Table
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Stoichiometry
- Using Dimensional Analysis
Explanation:
Step 1: Define
3.24 × 10²² molecules CH₃(CH₂)₈(OH)₂
Step 2: Identify Conversions
Avogadro's Number
[PT] Molar Mass of C - 12.01 g/mol
[PT] Molar Mass of H - 1.01 g/mol
[PT] Molar Mass of O - 16.00 g/mol
Molar Mass of CH₃(CH₂)₈(OH)₂ - 12.01 + 3(1.01) + 8[12.01 + 2(1.01)] + 2[16.00 + 1.01] = 161.3 g/mol
Step 3: Convert
- Set up: [tex]\displaystyle 3.24 \cdot 10^{22} \ molecules \ CH_3(CH_2)_8(OH)_2(\frac{1 \ mol \ CH_3(CH_2)_8(OH)_2}{6.022 \cdot 10^{23} \ molecules \ CH_3(CH_2)_8(OH)_2}) \cdot (\frac{161.3 \ g \ CH_3(CH_2)_8(OH)_2}{1 \ mol \ CH_3(CH_2)_8(OH)_2})[/tex]
- Multiply/Divide: [tex]\displaystyle 8.67838 \ g \ CH_3(CH_2)_8(OH)_2[/tex]
Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
8.67838 g CH₃(CH₂)₈(OH)₂ ≈ 8.68 g CH₃(CH₂)₈(OH)₂
