Respuesta :
Given that,
Mass of a water balloon, m = 1 kg
It comes downward an experience a 4.9 N air resistance as it approaches the ground.
To find,
The acceleration of the water balloon when it experiences this air resistance.
Solution,
Let the acceleration be a.
The net force acting on it will be :
[tex]F_{net}=mg+F_r\\\\=1\times 10+(-4.9)\\\\=5.1\ N[/tex]
The force is also given by :
F = ma
[tex]a=\dfrac{F}{m}\\\\a=\dfrac{5.1}{1}\\\\=5.1\ m/s^2[/tex]
So, the acceleration of the water balloon is [tex]5.1\ m/s^2[/tex].
The acceleration of the balloon when it experiences the air resistance is 4.9 m/s².
What is acceleration?
Acceleration is the rate of change of velocity.
To calculate the acceleration of the ballon when it experiences the air resistance, we use the formula below.
Formula:
- ma = mg-F'............... Equation 1
Where:
- m = mass of the ballon'
- a = acceleration of the ballon
- F' = air resistance
- g = acceleration due to gravity.
Make a the subject of the equation
- a = (mg-F')/m................. Equation 2
From the question,
Given:
- m = 1 kg
- F' = 4.9 N
- g = 9.8 m/s²
Substitute these values into equation 2
- a = [(9.8×1)-4.9)/1
- a = (9.8-4.9)/1
- a = 4.9/1
- a = 4.9 m/s²
Hence, The acceleration of the balloon when it experiences the air resistance is 4.9 m/s².
Learn more about acceleration here: https://brainly.com/question/605631