A canoe team leaves the dock at a bearing of 25° south of east and paddles at a constant speed of 10
mph. There is a 2 mph current moving 80° west of south. What is the canoe's actual speed and
direction? Draw a diagram and show your work to justify your answer. Round the distance to the nearest
hundredth and the direction to the nearest degree. (5 points)

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Answer:

I’m pretty sure this one is right but I did get 75% on the assignment

Step-by-step explanation:

Ver imagen tylerwillbailey

The resultant speed will be equal to V = 5.59 mph.

What is a Speed?

Speed is defined as the ratio of the distance travelled by the object to the time taken by the object.

Given that:-

  • A canoe team leaves the dock at a bearing of 25° south of east and paddles at a constant speed of 10mph.
  • There is a 2 mph current moving 80° west of south. What are the canoe's actual speed and direction?

The resultant speed will be calculated as:-

V = √{v₁  +  v₂ + v₁v₂SinФ)

V  = √ (10  +  2  +  ( 10 x 2 x Sin105 ) )

V =  5.59 mph

Therefore the resultant speed will be equal to V = 5.59 mph.

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