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A lab cart flies off the end of a track on a lab table with a horizontal velocity of 2.08 m/s. If it lands 0.96 meters from the edge of the table, how tall is the table?
A)0.5 m
B)6.0 m
C)1.2 m
D)2.2 m
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Respuesta :

Eduard22sly

Answer:

Option C. 1.2 m

Explanation:

The following data were obtained from the question:

horizontal velocity (u) = 2.08 m/s

Horizontal distance (s) = 0.96 m

Height (h) of the table =?

Next, we shall determine the time taken for the lab cart to get to the ground. This can be obtained as follow:

horizontal velocity (u) = 2.08 m/s

Horizontal distance (s) = 0.96 m

Time (t) =?

s = ut

0.96 = 2.08 × t

Divide both side by 2.08

t = 0.96 / 2.08

t = 0.5 s

Finally, we shall determine the height of the table as illustrated below:

Time (t) = 0.5 s

Acceleration due to gravity (g) = 9.8 m/s²

Height (h) of the table =?

h = ½gt²

h = ½× 9.8 × 0.5²

h = 4.9 × 0.25

h = 1.2 m

Thus, the height of the table is 1.2 m

Answer:

C) 1.2 m

Explanation:

Horizontal velocity = 2.08 m/s

Time taken to reach the ground :

t = 0.96 m/2.08m/s = 0.46 s

Strait down motion :

vi = 0

=> h = 4.9t^2 (a= 9.8 m/s^2)

= 4.9m/s^2*(0.46s)^2 = 1.04 m

The table is 1 m tall