A population of values has a normal distribution with μ = 245.3 and σ = 96 . You intend to draw a random sample of size n = 50 . Find the probability that a single randomly selected value is greater than 246.7. P(X > 246.7) = 0.0146 Incorrect Find the probability that a sample of size n = 50 is randomly selected with a mean greater than 246.7. P(M > 246.7) = Enter your answers as numbers accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.

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adefunkeadewole adefunkeadewole · Answer 1 · 2020-11-15T02:15:50+01:00

Answer:

0.4589

Step-by-step explanation:

We solve using z score formula

The z score formula for a random number of samples is:

z = (x-μ)/σ/√n, where x is the raw score, μ is the population mean, and σ is the population standard deviation

Hence:

z = 246.7 - 245.3/96/√50

z = 0.10312

Probability value from Z-Table:

P(x<246.7) = 0.54107

P(x>246.7) = 1 - P(x<246.7) = 0.45893

Approximately to 4 decimal places = 0.4589

The probability that a single randomly selected value is greater than 246.7 is 0.4589