so with the problem the equation for answering these would be “1.50t+4=c” so to plug in the variable for t would be 0, 1, 2, 3, etc. and the variable c would be the answer of solving the equation with the plugged in number
1.50(0)+4= $4.00
1.50(1)+4= $5.50
1.50(2)+4= $7.00
1.50(3)+4= $8.50
