Respuesta :
Answer:
45.8 cm
Explanation:
To solve this, we will use the formula
5 / x² = 7/(1 - x)²
5 / x² = 7 / (1 - 2x + x²)
5 / 7 = x² / (1 - 2x + x²)
x = 0.5 * (√(35) - 5) meters
x = 0.5 * (5.916 - 5)
x = 0.5 * (0.916)
x = 0.458 or x = 45.8
The position where the third charge is placed along the x-axis so that it does not experience any net force because of the other two charges is 45.8 cm.
Given :
Two point charges of magnitudes +5.00 μC, and +7.00 μC are placed along the x-axis at x = 0 cm and x = 100 cm, respectively.
The following calculation can be used in order to determine the position where the third charge is placed along the x-axis so that it does not experience any net force because of the other two charges.
[tex]\rm \dfrac{5}{x^2}=\dfrac{7}{(1-x)^2}[/tex]
Simplify the above expression by cross multiplying.
[tex]5(x^2+1-2x)=7x^2[/tex]
[tex]\rm 5x^2 + 5 - 10x = 7x^2[/tex]
[tex]2x^2+2x-1=0[/tex]
Further, simplify the above expression in order to determine the value of x.
x = 0.458
x = 45.8 cm
Therefore, the correct option is b).
For more information, refer to the link given below:
https://brainly.com/question/24391667
