Answer:
287.6g CHCl₃
Explanation:
We can determine the structure of Chloroform, dividing the mass of each element in its molar mass:
C = 12.0g * (1mol /12g) = 1 mol C
H = 1.01g * (1mol / 1.01g) = 1 mol H
Cl = 106.4g * (1mol / 35.45g) = 3 moles Cl
The structure is CHCl₃. And its molar mass is: 12.0g C +1.01g H + 106.4g Cl = 119.41g/mol
Now, the moles of carbon in the second sample = Moles of chloroform are:
28.9g C * (1mol / 12g) = 2.408 moles C = Moles CHCl₃
And its mass is:
2.408 moles CHCl₃ * (119.41g/mol) =