Respuesta :
Answer: C. (x+6) is a factor of p
Explanation:
p(-6) = 0 means that plugging x = -6 into p(x) leads to p(x) = 0.
If (x+6) was a factor of p(x), then we can say
p(x) = (x+6)q(x)
where q(x) is some other polynomial. Now let's replace x with -6
p(x) = (x+6)q(x)
p(-6) = (-6+6)q(-6)
p(-6) = 0*q(-6)
p(-6) = 0
The value of q(-6) doesn't matter as multiplying 0 with any number leads to 0.
This is all based on the special case of the remainder theorem that says "if p(k) = 0, then (x-k) is a factor of p(x)".
(x+6) is a factor of p.
The answer is option C.
How to solve the function?
p(-6) = 0 means that plugging x = -6 into p(x) leads to p(x) = 0.
If (x+6) was a factor of p(x), then we can say
p(x) = (x+6)q(x)
where q(x) is some other polynomial. Now let's replace x with -6
p(x) = (x+6)q(x)
p(-6) = (-6+6)q(-6)
p(-6) = 0*q(-6)
p(-6) = 0
The value of q(-6) doesn't matter as multiplying 0 with any number leads to 0.
This is all based on the special case of the remainder theorem that says "if p(k) = 0, then (x-k) is a factor of p(x)".
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