Complete Question
The complete question is shown on the first uploaded image
Answer:
The differential equation that fits the physical description is [tex]\frac{d (v(t))}{dt} = z [v(t)]^2[/tex]
Step-by-step explanation:
From the question we are told that
The acceleration due to air resistance of a particle moving along a straight line at time t is proportional to the second power of its velocity v, this can be mathematically represented as
[tex]a(t) \ \ \alpha \ \ \ [v(t)]^2[/tex]
Where [tex]a(t)[/tex] is the acceleration at time t
and [tex]v(t)[/tex] is the velocity at time t
So
=> [tex]a(t)= z [v(t)]^2[/tex]
Where z is a constant
Generally acceleration is mathematically represented as
[tex]a(t) = \frac{d (v(t))}{dt}[/tex]
So
[tex]\frac{d (v(t))}{dt} = z [v(t)]^2[/tex]
