Answer:
The tangential speed of Fayetteville, NC is 1372.2 km/h.
Explanation:
To find the tangential speed at the latitude 35 °N, first, we need to calculate the radius at that latitude [tex]r_{lat}[/tex]:
[tex] r_{lat} = r_{eq}*cos(\theta) [/tex]
Where:
[tex]r_{eq}[/tex]: is the equatorial radius = 6380 km
θ = 35 °
[tex] r_{lat} = r_{eq}*cos(\theta) = 6380 km*cos(35) = 5226.2 km [/tex]
Now, the tangential speed is:
[tex] v = \omega*r = \frac{2\pi}{23.93 h}*5226.2 km = 1372.2 km/h [/tex]
Therefore, the tangential speed of Fayetteville, NC is 1372.2 km/h.
I hope it helps you!
