Respuesta :
Answer:
[tex]\large \boxed{1.447 \times 10^{23}\text{ molecules Cu(OH)}_{2 }}[/tex]
Explanation:
1. Calculate the moles of copper(II) hydroxide
[tex]\text{Moles of Cu(OH)}_{2} = \text{23.45 g Cu(OH)}_{2} \times \dfrac{\text{1 mol Cu(OH)}_{2}}{\text{97.562 g Cu(OH)}_{2}} = \\\\\text{0.240 36 mol Cu(OH)}_{2}[/tex]
2. Calculate the molecules of copper(II) hydroxide
[tex]\text{No. of molecules} = \text{0.240 36 mol Cu(OH)}_{2} \times \dfrac{6.022 \times 10^{23}\text{ molecules Cu(OH)}_{2}}{\text{1 mol Cu(OH)}_{2}}\\\\= 1.447 \times 10^{23}\text{ molecules Cu(OH)}_{2}\\\text{The sample contains $\large \boxed{\mathbf{1.447 \times 10^{23}}\textbf{ molecules Cu(OH)}_{\mathbf{2}}}$}[/tex]
Answer:
Mass of Cu(OH)2 = 23.45 g
Molar mass of Cu(OH)2 = 97.562 g/mol
Since we know,
Moles = Mass/Molar mass
\Rightarrow Moles = (23.45 g)/(97.562 g/mol) = 0.2404 moles
Since 1 mole of substance contains = 6.022 × 1023 molecules
So 0.2404 moles will contain = 0.2404*(6.022 × 1023 molecules) = 1.448 × 1023 molecules
Explanation: