Answer:
Step-by-step explanation:
Let the litre of silver iodide be x
10% of silver iodide = 10% of x = 0.1x
4% of 3L of silver iodide= 4% of 3 = 0.04 × 3 = 0.12
The resulting mixture is 6% of solution, I.e 6% of (x + 3) = 0.06(x+3) = 0.06x + 0.18
Then,
10% of x + 4% of 3 = 6% of (x + 3)
0.1x + 0.12 = 0.06x + 0.18
0.1x - 0.06x = 0.18 - 0.12
0.04x = 0.06
x = 0.06 / 0.04
x = 1.5L
Then, 1.5L of 10% silver iodide will be added to 3L of 4% silver iodide to give 6% of silver iodide
