How do I find the area of a square using Pythagorean theorem
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Answer:
You have to find the hypotenuses of the triangle to get the area of the entire area of the shape. Once you have the length of the hypotenuses then you can use that value to calculate the area of the triangle and the area of the box above.
Hyp = sqRoot ( 3.16^2 + 6.32^2) = sqroot(50) = 7.07
Area of Triangle = 1/2 x b x h = 1/2 x 6.32 x 3.16 = 9.99= 10
Are of square above triangle = l x w = 7.07 x 7.07 = 49.99 = 50
Total area = 10 + 40 +10 +50 = 110 SQ UNITS
Step-by-step explanation:
The area of the required square is 50.
If the area of a square = 10
Then the side length = [tex]\sqrt{10}[/tex].
If the area of a square = 40
Then the side length = [tex]\sqrt{40}[/tex].
So the legs are [tex]\sqrt{10},\sqrt{40}[/tex].
So using pythegaorean identity the hypotenuse is = [tex]\sqrt{\left(\sqrt{10}\right)^{2}+\left(\sqrt{40}\right)^{2}} = \sqrt{10+40}=\sqrt{50}[/tex].
So the area of the required square is = [tex]\left(\sqrt{50}\right)^{2}=50[/tex].
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