Answer:
30.91% probability that the islanders will win exactly one out of four games in a series against the rangers
Step-by-step explanation:
For each game, there are only two possible outcomes. Either the Islanders win, or they do not. The probability of the Islanders winning a game is independent of other games. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
The probability that the islanders will beat the rangers in a game is 0.44
This means that [tex]p = 0.44[/tex]
What is the probability that the islanders will win exactly one out of four games in a series against the rangers?
This is P(X = 1) when n = 4. Then
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 1) = C_{4,1}.(0.44)^{1}.(0.56)^{3} = 0.3091[/tex]
30.91% probability that the islanders will win exactly one out of four games in a series against the rangers
Answer: 0.309 that’s for the delta math one
follow inst if it helped :3 miamarilyn22
Step-by-step explanation:
