Which function describes the graph below? On a coordinate plane, a curve has a maximum value of 6 and a minimum value of 0. It crosses the y-axis at (0, 6). f (x) = 6 cosine (x) f (x) = 3 cosine (x) + 3 f (x) = 6 sine (x) f (x) = 3 sine (x) + 3

Respuesta :

Answer:

I think the answer is b

Step-by-step explanation:

3cos(x)+3

The function that describes the given graph is:

f(x) = 3*cos(x) + x

Which function describes the graph?

Notice that in the description, we know that the graph intercepts the y-axis at (0, 6).

This means that f(0) = 6.

Now, just let's evaluate all the options in x = 0 and let's see if we can discard some of them.

  • a) f(0) = 6*cos(0) = 6
  • b) f(0) = 3*cos(0) + 3 = 6
  • c) f(0) = 6*sin(0) = 0
  • d) (0) = 3*sin(0) + 3 = 3

So. we can discard the two sine functions.

Now, we also know that the minimum value of our function is 0.

Notice that for the first option:

f(x) = 6*cos(x).

The maximum value is when cos(x) = 1, which gives 6, and the minimum value is when cos(x) = -1, which gives -6.

For the other option:

f(x) = 3*cos(x) + 3

The minimum is when cos(x) = -1, which gives:

3*-1 + 3 = -3 + 3 = 0

So we can conclude that this is the correct option.

f(x) = 3*cos(x) + x.

If you want to learn more about trigonometric functions, you can read:

https://brainly.com/question/8120556